(z^3)(1+i)z-2=

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Solution for (z^3)(1+i)z-2= equation: 


Simplifying
(z3)(1 + i) * z + -2 = 0

Reorder the terms for easier multiplication:
z3 * z(1 + i) + -2 = 0

Multiply z3 * z
z4(1 + i) + -2 = 0
(1 * z4 + i * z4) + -2 = 0

Reorder the terms:
(iz4 + 1z4) + -2 = 0
(iz4 + 1z4) + -2 = 0

Reorder the terms:
-2 + iz4 + 1z4 = 0

Solving
-2 + iz4 + 1z4 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + iz4 + 2 + 1z4 = 0 + 2

Reorder the terms:
-2 + 2 + iz4 + 1z4 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + iz4 + 1z4 = 0 + 2
iz4 + 1z4 = 0 + 2

Combine like terms: 0 + 2 = 2
iz4 + 1z4 = 2

Add '-1z4' to each side of the equation.
iz4 + 1z4 + -1z4 = 2 + -1z4

Combine like terms: 1z4 + -1z4 = 0
iz4 + 0 = 2 + -1z4
iz4 = 2 + -1z4

Divide each side by 'z4'.
i = 2z-4 + -1

Simplifying
i = 2z-4 + -1

Reorder the terms:
i = -1 + 2z-4

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